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x-x^2+0.64=0
We add all the numbers together, and all the variables
-1x^2+x+0.64=0
a = -1; b = 1; c = +0.64;
Δ = b2-4ac
Δ = 12-4·(-1)·0.64
Δ = 3.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3.56}}{2*-1}=\frac{-1-\sqrt{3.56}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3.56}}{2*-1}=\frac{-1+\sqrt{3.56}}{-2} $
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